Write a class to check whether a given number is Armstrong or not using a function name int checkArmstrong(int num). Function should return a value 1 if number is Armstrong otherwise return 0 .
Explanation :
An armstrong number is a number whose sum of the cubes of its digits is equal to the
number itself .
for example , 371 ----> 3*3*3 + 7*7*7 + 1*1*1 = 371
hence , 371 is an armstrong number .
import java.util.* ;
public class armstrong
{
public void check(int num)
{
int digit = 0 ;
int sum = 0 ;
int temp = num ;
int temp2 = num ;
int count = 0 ;
while(temp>0)
{
digit = temp%10 ;
temp = temp/10 ;
count++ ;
}
for(int i = 1 ;i<=count;i++)
{
digit = temp2%10 ;
temp2 = temp2/10 ;
sum = (int) (sum +
Math.pow(digit,count));
}
if(sum == num)
System.out.println(num+" is a Armstrong number .") ;
else
System.out.println(num+" is not a Armstrong number .") ;
}
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in) ;
System.out.println("Enter a number") ;
int num = sc.nextInt() ;
armstrong run = new armstrong() ;
run.check(num);
}
}
Codely Prompt ----->java armstrong.java
Enter a number
371
371 is a Armstrong number
